Solution PRD exercise page 32
- Need : 5 gallons can = mouthful
Know: Conversion 1.00 ft= 12.00 inches
& 1 gallon= 0.134 ft3
How: Use units analysis
Solve :
2. Need: For each part, conversion is ___________
(state whether definition, conversion factor, geometry, or scientific law)
Know: Basic concept s of conversion
factors, geometry and scientific laws. Also the diameter of the Earth 1is
12.756 km
How: For conversions use units method
Solve :
3. Need: Height 13 hands = ________ ft.
Know: Conversion factors: 16 hands/fathom
and 6.0 ft/fathom.
How: Method of units
Solve :
4. Need: Square mile = ________ acres.
Know: Conversion factors: 1609 m/mile, 104m2/hectare.
A team could plough 0.4 hectares/day = 1
acre/day. Thus 1.0 hectare =
2.5 acres.
How : Method of units
Solve :
5. Need : Area of orange skin = m2
Know: 39 inches/m
How : Method of units and a spherical
orange whose surface area is πD2
6.Need:Volume of apple = ________ in3.
Know:Conversion factors: 39 inches/m and 100 cm/m.
How:Method of units and assume a spherical
apple whose volume is
πD3/6.
7. Need:Tire pressure in SI units (N/m2)
Know:Use convert.exe2
for unit conversions. 1.00 lbf/in2= 6895
N/m2.
How:Method of units
8. Need: Wt of 50.0 slugs in lbf
Know: 1.00 slug is defined as F/g with F in
lbf and g in
How: Use eqn 2.3 of text
9. 9. Need: Mass of 5.0 slug on the Moon
Know - How: Mass is a property
Solve: m = 5.00 slugs anywhere in the
Universe.
10 .Need: Force on a body of mass 856 g (= 0.856 kg)
accelerated at 9.81 m/s2
Know: Newton’s Law of Motion, F = ma
How: F in N, m in kg and a in m/s2
11. Need: Wt of body on the Moon
Know: Mass = 0.102 kg, acceleration = 1.64
m/s2
How:Newton’s Law of Motion, F = ma or W= mgmoon
12. Need:Force to accelerate 735 lbm by 15.0 m/s2
Know: Need proportionality constant, gc=
32.2 lbm ft/lbf s2
How: Newton’s Law of Motion, F = ma/gc
13. Need:Value and units of gc in the
Engineering English system on the Moon
Know – How: gc is a proportionality
constant to convert units.
14. Need:Acceleration of car = ________ g’s.
Know:1.0g= 9.8 m/s2and acceleration is the rate of change of
speed withtime.
How:Method of units and conversion factor
of 60. mph = 88 ft/s (i.e.,
60/3600 ×5280
[miles/hr][hours/s][ft/mile].Also that 1 ft = 0.3048 m.
15. Need:Ratio of body mass in kg/weight in pounds = ________ kg/lbf.
Know: assume your mass in Mkg. Conversion factor = 2.20 lbm/kg. Also weight is a force that, in the English Engineering system, is mg/gc where m is your body mass in lbm.
How:Method of units and weight is a force that, in the English
Engineering system, is W= mg/gc where m is your body mass in lbm.
16. Need:Power of car = ________ W.
Know:Power of 1W = 1 J/s and 1 J = 1 N ×1 m, speed in m/s.
How:Method of units and 1 watt of power = 1 (N ×m)/s = 1 (N ×m/s)
17. Need: Time to 60.0 mph (26.8 m/s) and # of
g’s on a rocket sled.
Know:Newton’s law, a = F/m; g= 9.81 m/s2
. Also t = v/a(v is speed) since a= v/t.
How:Method of units and inverted Newton’s
law expressed in # g’s = a/g =
(F/m)g= F/mg.
19.Need: a) Massa of moon
apple=_________lbm and
b) weight of moon apple=________lbf
Nama Anggota Kelompok 5 (Kelas 10 PRD)
1. Arsi Amallah Binhaq (16514059)
2. Ahmad Sena Musa Satria(16514359)
3. Nur Latifah Ulfah(16514347)
4.Lara Yudillah(16514221)
5.Siti Sundari Fatimah(16514107)
Reference: Exploring Engineering second edition by Philip Kosky
Solusi soal PRD hal 32 by kelompok 5
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